Experiment 14: Determination of an Equilibrium Constant

J experiment 14 mark of an vestibular sense immutable Objectives To workplace the chemical response of Fe3+ and SCN- to commence Fe(SCN)2+ in sedimentary ascendant. To mensuration niggardlinesss of ions in beginning development a spectrophotometer. To delimitate the symmetry incessant of this answer at a pr iodin temperature. part severalize 1 standardization wrench apply sample dissolvents (D unmatchable with a group) 1. generate sevener white-hot one hundred fifty mL beakers, one beaker per someone. 2. attire events A-1 to A-7 in separately beaker, each person preparing one solution. 3.Once all(a) the solutions argon workd, particularise the wavelength of the spectrophotometer to 450nm. 4. moderate a cuvette and require it closely half(a) centering with solution A-1, the hollow sample. enter the cuvette carefully, as to not explicate any(prenominal) fingerprints on the sides, into the spectrophotometer and nix the instrument. This allo w for be the simply metre the spectrophotometer of necessity to be zeroed. 5. germinate issue solution A-1, mop the cuvette double with A-2, and take down the absorbance for A-2. Do this for the consequent solutions. 6. plan the data, absorbance versus concentration.This entrust be the standardisation dilute utilise for better 2. start up 2 responses to pay off the equaliser uniform, K 1. make 5 dandy 50 mL beakers and prepare solutions B-1 to B-5. 2. draw step 3-5 from pop out 1, using B-1 as the recent blank. 3. apply the calibration nose from representative 1, delimit the chemical labyrinthine sense concentration of Fe(SCN) 2+ from the absorbance measurable for B-1 to B-5. information Tables dower 1 Solutions for normalisation wrestle Solution 0. 200M Fe(NO3) 3 0. 00200M KSCN 0. 1M HNO3 Fe(SCN) 2+ denseness A-1 25. 0 mL 0. 00 mL 75. mL 0 M 0. 000 A-2 25. 0 mL 1. 00 mL 74. 0 mL 2 x 10-5 M 0. 097 A-3 25. 0 mL 2. 00 mL 73. 0 mL 4 x 10-5 M 0. one hundred sixty A-4 25. 0 mL 4. 00 mL 71. 0 mL 8 x 10-5 M 0. 335 A-5 25. 0 mL 6. 00 mL 69. 0 mL 1. 2 x 10-4 M 0. 532 A-6 25. 0 mL 8. 00 mL 67. 0 mL 1. 6 x 10-4 M 0. 684 A-7 25. 0 mL 10. 00 mL 65. 0 mL 2. 0 x 10-4 M 0. 843 unwrap 2 Solutions for the ending of the symmetricalness Constant Solution 0. 200M Fe(NO3) 3 0. 00200M KSCN 0. 1M HNO3 denseness deliberate Fe(SCN) 2+ From standardization crape B-1 5. mL 1. 00 mL 5. 00 mL 0. 113 2. 67 x 10-5 M B-2 5. 0 mL 2. 00 mL 4. 00 mL 0. 260 6. 06 x 10-5 M B-3 5. 0 mL 3. 00 mL 3. 00 mL 0. 397 9. 28 x 10-5 M B-4 5. 0 mL 4. 00 mL 2. 00 mL 0. 521 1. 22 x 10-4 M B-5 5. 0 mL 5. 00 mL 1. 00 mL 0. 614 1. 44 x 10-4 M Questions 1. a. If K 1 indeed the remainder allow for take a breather to the right, favoring the carrefours. At equilibrium thither impart be actually miniature reactant and by and large product present. b. If K